When we call the function with (1, 5) it removes the least recently used results of (1, 2)
So next time it has to be computed again.
import functools
@functools.lru_cache(maxsize=3)
def compute(x, y):
print(f"Called with {x} and {y}")
# some long computation here
return x+y
compute(1, 2) # Called with 1 and 2
compute(1, 2)
compute(1, 2)
compute(1, 3) # Called with 1 and 3
compute(1, 3)
compute(1, 4) # Called with 1 and 4
compute(1, 4)
compute(1, 5) # Called with 1 and 5
compute(1, 2) # Called with 1 and 2
compute(1, 2)